From the given discrete distribution, we have that:
<h3>What are the mean, the variance and the standard deviation of a discrete distribution?</h3>
- The mean of a discrete distribution is given by the sum of each outcome multiplied by it's respective probability.
- The variance is given by the sum of the difference squared between each observation and the mean, divided by the number of values.
- The standard deviation is the square root of the variance.
In this problem, the distribution is:
Hence, the mean is:
The variance is:
The standard deviation is:
More can be learned about discrete distributions at brainly.com/question/24855677
Answer:
3/20
Step-by-step explanation:
Answer: you will have 56
Step-by-step explanation:
<span>Ans : Note that:
sin(x) = sum(n=0 to infinity) [(-1)^n * x^(2n + 1)]/(2n + 1)!.
Then, since the series is alternating, the error in the approximation found by taking the first n terms of the series is no bigger than the n+1'th term. In other words:
E ≤ a_n+1 = x^(2n + 3)/(2n + 3)!.
(Note that a_n does not include (-1)^n, the alternating part)
We need that 1/6 ≤ x^(2n + 3)/(2n + 3)!. Given |x| < 1, n = 2 will be the least integer solution. Thus, we need 2 + 1 = 3 terms.</span>
