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Keith_Richards [23]
3 years ago
5

Solve for d when 2x-2yd=y+xd ...?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
3 0
2x-2yd=y+xd 2x-y=xd+2yd 2x-y=d(x+2y) (2x-y)/(x+2y)=d So the answer is <span><span>d=<span><span>2x−y</span><span>x+2y</span></span></span></span>
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olya-2409 [2.1K]

Answer:

f(n)=64(\frac{1}{4})^{n-1}

Step-by-step explanation:

The given sequence is

64, 16, 4, 1

r_1=\dfrac{a_2}{a_1}=\dfrac{16}{64}=\dfrac{1}{4}

r_2=\dfrac{a_3}{a_2}=\dfrac{4}{16}=\dfrac{1}{4}

r_3=\dfrac{a_4}{a_3}=\dfrac{1}{4}

It is a geometric series because it has a common ratio r_1=r_2=r_3=\dfrac{1}{4}.

First term is 64.

The explicit formula of a geometric series is

f(n)=ar^{n-1}

where, a is first term and r is common ratio.

Substitute a=64 and r=1/4 in the above function.

f(n)=64(\frac{1}{4})^{n-1}

Therefore, the required explicit formula is f(n)=64(\frac{1}{4})^{n-1}.

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