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alex41 [277]
3 years ago
12

(x+4)−(x−1)

Mathematics
2 answers:
Gekata [30.6K]3 years ago
5 0

Answer:

There is no plug-in for x.

X=0.

(0+4) - (0-1) = [(4 - (-1)] = 5.

raketka [301]3 years ago
4 0

Answer:

5

Step-by-step explanation:

(x+4) -x +1

x - x = 0

5

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If a polynomial has four terms, 3x3 5x 6x2 10, which factoring method can be considered? perfect-square trinomial difference of
Tems11 [23]

The factoring method which can be considered for such a cubic tetranomial expression is; factor by grouping sum of cubes.

<h3>What factoring method can be considered for the polynomial?</h3>

It follows from the task content that the order of the Polynomial is 3 and the polynomial is a tetranomial as it contains 4 terms.

On this note, since 3x³ is not a perfect cube, it follows that the best factorisation method for such a polynomial is; factor by grouping sum of cubes.

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8 0
2 years ago
When the sum of \, 528 \, and three times a positive number is subtracted from the square of the number, the result is \, 120. F
aleksandr82 [10.1K]

Let x be the unknown number. So, three times that number means 3x, and the square of the number is x^2

We have to sum 528 and three times the number, so we have 528+3x

Then, we have to subtract this number from x^2, so we have

x^2-(3x+528)

The result is 120, so the equation is

x^2 - 3x - 528 = 120 \iff x^2 - 3x - 648 = 0

This is a quadratic equation, i.e. an equation like ax^2+bx+c=0. These equation can be solved - assuming they have a solution - with the following formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

If you plug the values from your equation, you have

x_{1,2} = \dfrac{3\pm\sqrt{9-4\cdot(-648)}}{2} = \dfrac{3\pm\sqrt{9+2592}}{2} = \dfrac{3\pm\sqrt{2601}}{2} = \dfrac{3\pm51}{2}

So, the two solutions would be

x = \dfrac{3+51}{2} = \dfrac{54}{2} = 27

x = \dfrac{3-51}{2} = \dfrac{-48}{2} = -24

But we know that x is positive, so we only accept the solution x = 27

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3 years ago
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The expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

<h3>How to rewrite the statement as an expression?</h3>

The mathematical statement is given as

Jaun's age, x, is 4 times his age 15 years ago

From the statement, we have:

x represent Juan's current age

This means that his age 15 years ago is

15 years ago = x - 15

4 times his age 15 years ago is

4 * 15 years ago = 4 * (x - 15)

The above equation is equivalent to his current age

So, we have

x = 4 * (x - 15)

Hence, the expression of the mathematical statement given as "Jaun's age, x, is 4 times his age 15 years ago" is x = 4 * (x - 15)

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