Answer:
The point is at about (4.5, 100).
Step-by-step explanation:
Minka's line is p = 22t, which has a y-intercept of 0.
Kenji's line is p = 50 + 11t, which has a y-intercept of 50.
Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).
You can find this point by setting the two equations equal to each other:
22t = 50 + 11t
Subtract 11t from both sides.
11t = 50
t = 50/11 ≈ 4.545
Then you can find the p value for this point by plugging t = 4.545 into either equation.
p = 22(4.545) = 99.99
p = 50 + 11(4.545) = 99.995
On the graph the point is about (4.5, 100).
It would be $2.25
if each student pays one more penny than the last one the penny count would be up to 150 pennies times the number of student which is 150 so multiply and add your decimal
The differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵
<h3>What is differentiation?</h3>
The method of determining the derivative, or rate of change, of a function in mathematics.is termed as the differentiation.
Given that:-

The derivative will be calculated as:-

Therefore the differentiation of the function g(t) = 7/t⁴ will be equal to g¹(t)=-28/t⁵
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Usando un sistema de ecuaciones, se encuentra que
- Cada manzana cuesta $3.
- Cada pera cuesta $1.
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- Un sistema de ecuaciones soluciona esta pergunta.
- El custo de una manzana es x.
- El custo de una pera es y.
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- <u>Seis manzanas y 8 peras cuestan $26</u>, o sea,

- <u>Cada manzana cuesta el triple de cada pera</u>, o sea,

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Primero, encontramos el cuesto de una pera, substituyendo la segunda en la primera ecuación.






Cada pera cuesta $1.
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<u>Cada manzana cuesta el triple de cada pera</u>, o sea,
.
Cada manzana cuesta $3.
Se encuentra um problema similar en brainly.com/question/24646137
Answer:
first option 1/2
Step-by-step explanation:
2,3,5 are the prime numbers from that set
each individual number has a 1 in 6 chance of landing on it and we have 3 so...
3 of 6 possibilities would be prime numbers. Simplify to...
1 in 2