Question

A random sample of 65 bags of white cheddar popcorn​ weighed, on​ average, 5.74 ounces with a standard deviation of 0.26 ounce. Test the hypothesis that muequals5.8 ounces against the alternative​ hypothesis, muless than5.8 ​ounces, at the 0.10 level of significance.

Answer 1

Answer:

We failed to accept null hypothesis

Step-by-step explanation:

x= 5.74

Standard deviation = $0.26$

$H_0:\mu = 5.8\\H_a:\mu < 5.8$

n = 65

We will use z test

Formula : $z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

Substitute the values :

$z=\frac{5.74-5.8}{\frac{0.26}{\sqrt{65}}}$

$z=-1.86$

Refer the z table for p value

p value = 0.0314

α = 0.10

p value < α

So, we failed to accept null hypothesis