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Vesna [10]
3 years ago
6

Six less than a number is negative two? In a equation

Mathematics
1 answer:
Zina [86]3 years ago
3 0

Answer:

x-6=-2

Step-by-step explanation:

Let x, be "a number".

6 less, would be x-6. "Is" means equals ( = )

You then can put that together to get your equation.

<em>Hope this helps!!!</em>

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What is the sum of the given polynomials in standard form ? (X^2-3x)+(-2x^2+5x-3)
Greeley [361]
(x^2-3x)+(-2x^2+5x-3)=x^2-3x-2x^2+5x-3\\\\=(x^2-2x^2)+(-3x+5x)-3=-x^2+2x-3
3 0
3 years ago
In parallelogram EFGH, the measure of angle G is (4x + 16)° and the measure of angle H is (2x − 16)°. What is the measure of ang
asambeis [7]

Answer:

m∠H = 44°

Step-by-step explanation:

Consecutive angles of a parallelogram are supplementary.  So,

∠H and ∠G are supplementary

4x + 16 + 2x - 16 = 180

6x = 180

x = 30

m∠H = 2x - 16 = 2(30) - 16 = 60 - 16 = 44°

4 0
2 years ago
1. In the Rundhalser, 200 bags of popcorn were put out. At the end of the day,
natali 33 [55]

Answer:

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Step-by-step explanation:

6 0
2 years ago
Which equation is the inverse of 2(x - 2)2 = 8(7 + y)?
Marina86 [1]

Answer:

The inverse of 2(x - 2)^2 = 8(7 + y) is y=\sqrt{(4x+28)}+2

Step-by-step explanation:

Given equation :2(x - 2)^2 = 8(7 + y)

\Rightarrow \frac{2(x-2)^2}{8}=7+y\\\Rightarrow \frac{2(x-2)^2}{8}-7=y

Replace x with y and y with x

So, \Rightarrow \frac{2(y-2)^2}{8}-7=x\\\Rightarrow \frac{2(y-2)^2}{8}=x+7\\\Rightarrow 2(y-2)^2=8(x+7)\\\Rightarrow (y-2)^2=4(x+7)\\\Rightarrow (y-2)=\sqrt{4(x+7)}\\\Rightarrow y=\sqrt{4(x+7)}+2\\\Rightarrow y=\sqrt{4x+28)}+2

So, Option C is correct

Hence The inverse of 2(x - 2)^2 = 8(7 + y) is y=\sqrt{(4x+28)}+2

4 0
2 years ago
Find the TWO integers whos product is -12 and whose sum is 1<br>​
Deffense [45]

Answer:

\rm Numbers = 4 \ and \ -3.

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}

Hence the numbers are 4 and -3

4 0
2 years ago
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