Ask question

Ask question

All categories

3 years ago

6

Six less than a number is negative two? In a equation

1 answer:

Zina [86]3 years ago

3 0

Answer:

$x-6=-2$

Step-by-step explanation:

Let $x$ , be "a number".

6 less, would be $x-6$ . "Is" means equals ( = )

You then can put that together to get your equation.

<em>Hope this helps!!!</em>

You might be interested in

The smaller triangle is the image of the larger triangle after a dilation. The center of the dilation is (4,2). What is the scal

zzz [600]

Small triangle: <span>The side // x axis has a length of 4
Large triangle: The side // x axis has a length of 12

So Small/Large = 4/12 = 1/3

Small triangle: <span>The side // y axis has a length of 3
Large triangle: The side // y axis has a length of 9

</span><span>So Small/Large = 3/9 = 1/3

So the scale factor to obtain this dilatation is 1/3</span>

</span>

7 0

3 years ago

Read 2 more answers

Hey i need some help :)

melamori03 [73]

Answer:

[See Below]

Step-by-step explanation:

$\boxed{Hey~There!}$

__________________________________________________________

$\boxed{Solve~-3x$

Rearrange the equation by subtracting what is to the right of the greater than sign (≤, ≥) from both sides of the inequality:

$-3*x-(9)$

Pull out like factors:

$-3x - 9 = -3 * (x + 3)$

Divide both sides by $-3$ :

Remember to flip the inequality sign:

Subtract $3$ from both sides:

$x > -3$

$\boxed{The~answer~is: x > -3}$

$\boxed{The~answer~is: C}$

__________________________________________________________

$Hope~this~helps~Mate!\\-Your~Friendly~Answerer,~Shane$ ^-^

8 0

3 years ago

The sides of a square are 2^4/9 inches long. what is the area of the square?

bagirrra123 [75]

The Area of the square is (side)^2

side is given to be 2^(4/9)
SO,
side^2 = [2^(4/9)]^2 = 2^(4/9 * 2) = 2^(8/9)
so the area of square is 2^(8/9) sq. inches.

5 0

3 years ago

Solve each trigonometric equation such that 0 ≤ x ≤ 2????. Give answers in exact form.

sveticcg [70]

Answer:

(a) $x=\frac{5\pi }{3}$

(b) $x=\frac{\pi }{8}$

Step-by-step explanation:

It is given that $0\leq x\leq 2\pi$

(a) We have given equation $2sinx+\sqrt{3}=0$

$sinx=\frac{-\sqrt{3}}{2}$

$x=sin^{-1}(-0.866)$

$x=\frac{-\pi }{3}=2\pi -\frac{\pi }{3}=\frac{5\pi }{3}$

(b) $tan(2x)=1$

$2x=tan^{-1}1$

$2x=\frac{\pi }{4}$

$x=\frac{\pi }{8}$

7 0

4 years ago

1. Which two points fail the VLT here in this graph?<br><br><br> PLEASE HELP!!!!

ivolga24 [154]

Kiki and Rose's points

They are on the same vertical line so they fail

4 0

3 years ago