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DIA [1.3K]
3 years ago
15

Write a C++ program that prompt the user to enter three points (x1, y1), (x2, y2), (x3,y3) of a triangle and displays its area.

Computers and Technology
1 answer:
maxonik [38]3 years ago
5 0

Answer:

Here is the code in c++.

//include headers

#include <bits/stdc++.h>

using namespace std;

//main function

int main() {

//variables to store coordinates

float x1,x2,y1,y2,x3,y3;

cout<<"Please Enter the coordinate of first point (x1,y1): ";

// reading coordinate of first point

cin>>x1>>y1;

cout<<"Please Enter the coordinate of second point (x2,y2): ";

// reading coordinate of second point

cin>>x2>>y2;

cout<<"Please Enter the coordinate of third point (x3,y3): ";

// reading coordinate of third point

cin>>x3>>y3;

//calculating area of the triangle

float area=abs((x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2))/2);

cout<<"area of the triangle:"<<area<<endl;

return 0;

}

Explanation:

Declare four variables x1,x2,x3,y1,y2,y3 to store the coordinate of all three

points of circle.Read the coordinate of all the point from user.Calculate area of triangle with the help of mentioned formula area=abs((x1*(y2-y3)+x2*(y3-y1)+x3*(y1-y2))/2). Then print the area of the triangle.

Output:

Please Enter the coordinate of first point (x1,y1): 11 17                                                                                                      

Please Enter the coordinate of second point (x2,y2): 23 30                                                                                                    

Please Enter the coordinate of third point (x3,y3): 43 18                                                                                                      

area of the triangle:202  

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3 years ago
Output a table that show the cube of the numbers 1-15<br> (C++)
Rainbow [258]

Answer:

The c++ program to display cube of numbers from 1 to 15 is given below.

#include <iostream>

using namespace std;

int main() {    

   // variables declared and initialized  

   int num = 15, k, cube;    

   cout << " Cubes of numbers from 1 to 15 are shown below " << endl;    

   for( k = 1; k <= num; k++ )

   {

       // cube is calculated for each value of k and displayed

       cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

return 0;

}

 

OUTPUT

Cubes of numbers from 1 to 15 are shown below  

  1

  8

  27

  64

  125

  216

  343

  512

  729

  1000

  1331

  1728

  2197

  2744

  3375

Explanation:

The variables are declared and initialized for loop, cube and for condition in the loop – k, cube, num respectively.

Inside for loop which executes over k, beginning from 1 to 15, cube of each value of k is calculated and displayed. The loop executes 15 times. Hence, cube for numbers from 1 to 15 is displayed after it is calculated.

   for( k = 1; k <= num; k++ )

   {

      cube = k * k * k ;

       cout << " \t " << cube << endl;

   }

In the first execution of the loop, k is initialized to 1 and variable cube contains cube of 1. Hence, 1 is displayed on the screen.

In the second execution, k is incremented by 1 and holds the value 2. The variable cube contains cube of 2, which is calculated, and 8 gets displayed on the screen.

After each execution of the loop, value of k is incremented.

After 15 executions, value of k is incremented by 1 and k holds the value 16. This new value is greater than num. Hence, the loop terminates.

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Explanation:

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Create a Boolean function odd_number_digits(n) that returns True when a positive integer has an odd number of digits. (You may a
Snowcat [4.5K]

Answer:

Following are the code to this question:

import java.util.*;//import package for user input

public class Main//defining class main

{

   public static boolean odd_number_digits(int n)//defining boolean method odd_number_digits

   {

       if(n>0 && n%2!=0)//defining if block that check value is positive and odd number

       {

       return true;//return value true

       }

       else//defining else block

       {

           return false;//return false value

       }

   }

   public static void  sum_odd_digits(int n)//defining a method sum_odd_digits

   {

       int sum=0,i;//defining integer variable

       for(i=0;i<=n;i++)//defining for loop

       {

           if(i%2!=0)//defining if block for odd number

           {

               sum=sum+i;//add odd number

           }

       }

      System.out.print(sum);//use print method to print sum value

   }

public static void main(String[] args) //defining main method

   {

       Scanner ox=new Scanner(System.in);//creating Scanner object

       int n= ox.nextInt();//defining integer variable for input value

       System.out.print(odd_number_digits(n)+ "\n");//use print method to call method

       System.out.println("Sum of odd numbers: ");//print message

       sum_odd_digits(n);//calling method

   }

}

Output:

please find the attachment.

Explanation:

In the above code, two methods "odd_number_digits and sum_odd_digits" are defined in which the first method return type is boolean because it will true or false value, and the second method returns the sum of odd numbers.

In the "odd_number_digits" method,  an integer variable passes as an argument and inside the method, if block is used that check value is a positive and odd number then it will return a true value.

In the "sum_odd_digits" method, it accepts an integer parameter "n", and define integer variable "sum" inside the method, which uses the for loop, inside the loop if block is used that counts odd numbers and adds its in sum and print its value.

8 0
3 years ago
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