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mario62 [17]
3 years ago
12

The measures of a three sides of a triangle can be represented by the algebra expressions x, 3x-1, and 4x 2. the perimeter of th

e triangle is 81 inches. what are the lengths of the sides of the triangle?
Mathematics
1 answer:
umka2103 [35]3 years ago
3 0
Perimeter of triangle= 81
x+3x-1+4x-2=81
8x-3=81
8x=84
x=10.5 so sides are 10.5,30.5,40.
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Answer:

W=7 L= 16

Step-by-step explanation:

you start off with

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the equation gives you the perimeter = 46

so you plug that in

     46=2L +2W

then it says the length IS (which also means equals) 9 plus the width

so you then get another equation:

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you take that and plus it into the first equation/ substitute the new equation for L in the first equation

     46=2(9+W)+2W

you solve that and get

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Kruka [31]

Answer:

x=112

Step-by-step explanation:

First, let's get all of the fractions to a common denominator.

Based on the numbers given (8,56, and 7), let's make all of the denominators be 56

for \frac{-7}{8} x, multiply the numerator and denominator by 7.

\frac{-7x}{8}×\frac{7}{7}= \frac{-49}{56} x

we can leave \frac{-5}{56}x as it is

and for \frac{1}{7} x, we cam multiply the numerator and denominator by 8

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Here's the equation now:

\frac{-49x}{56}-\frac{5x}{56}+\frac{8x}{56}=-92

now simlify the fractions

numerators:

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here's the fraction now:

\frac{-46x}{56}=-92

We can simplify the fraction by 2 so it's \frac{-23x}{28}

\frac{-23x}{28}=-92

now multiply both sides by \frac{28}{-23}, which is the reciprocal of \frac{-23}{28} (to isolate the variable)

\frac{28}{-23}×\frac{-23x}{28}=-92×\frac{28}{-23}

\frac{-92*28}{-23}

x=112

Hope this helps!

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