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Effectus [21]
3 years ago
8

Two vectors have magnitudes of 1.8 m and 2.4 m. How are these vectors arranged, so their sum is 0.6 m?

Mathematics
2 answers:
Cloud [144]3 years ago
7 0

They are arranged in opposite directions Answer ( 2.4 - 1.8 = 0.6)

erik [133]3 years ago
7 0

2

The two vectors would have to be in opposition to each other. You would then get 2.4 - 1.8 = 0.6

3

The magnitude is sqrt(1.4^2 + 4.8^2) = sqrt(1.96 + 23.04) = sqrt(25) = 5

The Direction is tan-1(4.8/1.4) = 73.74o and that is East of North. (Draw a diagram. Draw the North vector going vertically with a length of 1.4 and horizontally of 4.8). The tan-1(opposite over adjacent) is the angle you want.

4.

Draw a diagram showing the vertical distance as 1.2 and the horizontal distance as 1.6.

The magnitude is sqrt(1.2^2 + 1.6^2) = sqrt(4)= 2

The direction is tan-1(1.6/1.2) = 53o

The answer is A

5

The total horizontal distance is 7 + 5 = 12 miles

The total vertical distance = 2 + 3 = 5 miles

The magnitude of the displacement = sqrt(12^2 + 5^2) = sqrt(169) = 13

The direction tan-1(5/12)= 22.6o North of East.


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irina [24]

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6 0
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vodomira [7]
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3 years ago
Find x, y, and z.<br><br> Show all of your work for full credit.
Stella [2.4K]
If you can't read it, I'll do my best to translate:
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180 - 116.57 = 63.43°
5 ÷ sin(63.43) = 8.88 = Y

X) 11.18^2 + 8.88^2 = 203.8468
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All numbers are rounded to 2 decimal places, if you need any explanations for why I did something then just let me know :)
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