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Westkost [7]
2 years ago
8

Find the measure of angle b.

Mathematics
2 answers:
tensa zangetsu [6.8K]2 years ago
4 0

Answer:

60°

Step-by-step explanation:

Vertical angles are congruent.

sukhopar [10]2 years ago
4 0

Answer:

60 degrees

Step-by-step explanation:

You might be interested in
Which function is a quadratic function? u(x) = –x 3x2 – 8 v(x) = 2x2 8x3 9x y(x) = x2 3x5 4 z(x) = 7x2 2x3 – 3.
Komok [63]

The function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

Given functions are:

u(x)=-x+3x^{2} -8

v(x)=2x^{2} +8x^3+9x

y(x)=x^{2} +3x^5+4

z(x) =7x^{2} +2x^3-3

<h3>What is a quadratic function?</h3>

A function of the form f(x)=ax^{2} +bx+c with a\neq 0 is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

u(x)=-x+3x^{2} -8

Highest exponent =2

The function is also of form f(x)=ax^{2} +bx+c so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

To get more about quadratic functions visit:

brainly.com/question/1214333

7 0
2 years ago
What are the zeros of x (3 - 18x) = 0 ?
tresset_1 [31]

Answer:

x=3⋅±  2

​  

=±4.2426

x=0

Step-by-step explanation:

6 0
3 years ago
The Lakers won 35 games and lost 47 games. At this rate, how many games should they win, in a 96-game season?
Ede4ka [16]

Answer:

37 games if you were to round percents

5 0
3 years ago
Mary spent a total of $352.24 for a party. She spent $200.29 on food, plus an additional $30.39 for each hour of the party. How
FinnZ [79.3K]

The answer should be 5 hours.

8 0
3 years ago
Read 2 more answers
. Quantas senhas com 4 algarismos diferentes podemos escrever com os algarismos 1, 2, 3, 4, 5, 6?
ruslelena [56]

Answer:

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

Step-by-step explanation:

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

  • Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).
  • Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).
  • Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).
  • Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

So, the number of passwords with 4 different digits we can write = 6 \times 5 \times 4 \times 3  = 360 possibilities.

Hence, we can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

4 0
3 years ago
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