Question

Simplify using a table (6q+7)(2q+3)

Answer 1

Answer:

$\:\:\left(6q+7\right)\left(2q+3\right)=12q^2+32q+21$

Table is shown below

Step-by-step explanation:

Given expression  $\:\:\left(6q+7\right)\left(2q+3\right)$

We have to find the product of given expression using table.

Consider the given expression $\:\:\left(6q+7\right)\left(2q+3\right)$

We  have to find the product of given expression  $\:\:\left(6q+7\right)\left(2q+3\right)$

Apply FOIL METHOD,

Multiply Each term in first bracket with each term in second bracket,

 $\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

We have,

$=6q\cdot \:2q+6q\cdot \:3+7\cdot \:2q+7\cdot \:3$

Simplify, we have,

$=6\cdot \:2qq+6\cdot \:3q+7\cdot \:2q+7\cdot \:3$

Simplify, we have,

$=12q^2+32q+21$

Answer 2

 (6q+7)(2q+3)
12q^2 + 18q + 14q + 21
12q^2 + 32q + 21