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alex41 [277]
3 years ago
5

Find the length of line OC.

Mathematics
2 answers:
ziro4ka [17]3 years ago
8 0

Answer:

15

Step-by-step explanation:

stealth61 [152]3 years ago
6 0

If AB = 16, then AC is (1/2)(AB) or 8.

(OC)^2 + 8^2 = 17^2

(OC)^2 = 17^2 - 8^2

(OC)^2 = 289 - 64

(OC)^2 = 289 - 64

(OC)^2 = 225

Taking the square root on both sides leads to OC = 15 cm.

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Answer:

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For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

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Probability of exactly x sucesses on n repeated trials, with p probability.

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10 word errors.

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(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

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(b) What is the mean number of errors caught?

E(Y) = np = 10*0.7 = 7

The mean number of errors caught is 7.

What is the mean number of errors missed?

E(X) = np = 10*0.3 = 3

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491

The standard deviation of the number of errors missed is 1.4491.

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3 years ago
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