Answer:
Option B. $900
Step-by-step explanation:
Let
y ----> the value of the car
x ----> the time in years
we know that
The linear function in slope intercept form is equal to

where
m is the slope or the depreciation rate
b is the y-intercept or initial value of the car
we have
The y-intercept or initial value is equal to


we have the ordered pair (5,500)
substitute the value of x and the value of y of the ordered pair in the linear equation and solve for m


Is negative because is a decreasing function
The linear equation is equal to

therefore
It would depreciate $900 each year.
This is the concept of financial mathematics, the simple interest rate is given by:
S.I.=(PRT)/100
where:
P=principle=$2500
R=rate=5.5%
T=time=1 year
Hence;
S.I.=(5.5*2500.1)/100
=$137.5
Thus the total amount he had after 1 year will be:
2500+137.5
=$2,637.5
Answer:
18,36,54,72,90 are first five multiples of 18
Step-by-step explanation: