Answer:
1 is neither prime nor a composite number because it only has 1 divisor, 1 and 1, and it doesn't have more than 2 integral divisors, like stated, it only has 1. So it falls in neither category.
This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
Answer:
The coordinates are 6,5.
Step-by-step explanation:
Go over 6 and go up 5 and 6ou have your answer.