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Vinil7 [7]
3 years ago
13

(0, 4), (-5, 8), (4, -2), what is the range?

Mathematics
1 answer:
laila [671]3 years ago
4 0

Answer:

<h2>range={ -2,4,8}</h2>

Explanation:

Let R be a relation from A to B.Then the set of first components or the set of elements of A are called domain and <u>the</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>second</u><u> </u><u>compo</u><u>nents</u><u> </u><u>or</u><u> </u><u>the</u><u> </u><u>set</u><u> </u><u>of</u><u> </u><u>elements </u><u>of</u><u> </u><u>B</u><u> </u><u>are</u><u> </u><u>called</u><u> </u><u>the</u><u> </u><u>range</u><u>.</u>

Hope this helps...

Good luck on your assignment..

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3 years ago
What is the horizontal asymptote of the rational function f(x) = 3x / (2x - 1)?
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Answer:

Step-by-step explain

Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :

A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)

If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.

For the given function, there is no horizontal asymptote.

We can find the slant asymptote by using long division:

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The slant asymptote is y=3/2x+3/4

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Step-by-step explanation:

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