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ziro4ka [17]
3 years ago
11

Work out and simplify where possible

Mathematics
2 answers:
FromTheMoon [43]3 years ago
6 0

I hope it helps you ❤️❤️❤️

stiks02 [169]3 years ago
6 0

Answer:

a= 13/18 and b=5/16

Step-by-step explanation:

in A, multiply 4/9 by 2, you get 8/18 then add to it 5/18 you get 13/18

in B, multiply 3/8 by 2, you get 6/16 then subtract it by 1/16, you get 5/16

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Let f(x)=-2x+4 and g(x)=-6x-7 find f(x)-g(x)
Evgesh-ka [11]
f(x)=-2x+4\\ g(x)=-6x-7\\ \\ f(x)-g(x) = -2x+4 - (-6x-7)=-2x+4 +6x+7=4x+11


7 0
3 years ago
Read 2 more answers
Consider the system of equations. y = 3x + 2       y = − 2 3 x − 4 Explain why these particular equations can be graphed immedia
inessss [21]

Answer:

These equations are in slope-intercept form. I can use the y-intercept and slope to graph both lines. I plot the y-intercept and use rise over run to locate another point on the line. Then, I can draw a line through the two points.

Step-by-step explanation:

3 0
3 years ago
Answer please and explain
Andrej [43]
36 pairs
because 2 spots = 1 pair
so 2x=72
and your answer will be 36 pairs
4 0
3 years ago
The graph of F ( x ) = 4/x2 - 2x - 3 is shown <br> for which values of X is f ( x ) decreasing
Elza [17]

Hi there!

\large\boxed{(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty) }

We can find the values of x for which f(x) is decreasing by finding the derivative of f(x):

f(x) = \frac{4}{x^2} - 2x - 3

Taking the derivative gets:

f'(x) = -\frac{8}{x^3} - 2

Find the values for which f'(x) < 0 (less than 0, so f(x) decreasing):

0 = -8/x³ - 2

2 = -8/x³

2x³ = -8

x³ = -4

x = \sqrt[3]{-4}

Another critical point is also where the graph has an asymptote (undefined), so at x = 0.

Plug in points into the equation for f'(x) on both sides of each x value to find the intervals for which the graph is less than 0:

f'(1) = -8/1 - 2 = -10 < 0

f'(-1) = -8/(-1) - 2 = 6 > 0

f'(-2) = -8/-8 - 2 = -1 < 0

Thus, the values of x are:

(-\infty, \sqrt[3]{-4}) \text{ and } (0, \infty)

6 0
3 years ago
Change the following algebraic expressions to the statement in words: i. 3mn +7 ii. xy + (x+y)
kicyunya [14]

Answer:

i) 3*m*n + 7

Then we can write the first term as:

"3 times the product between two numbers"

Where the product of two numbers is m*n

And after that we need to add 7, then the complete sentence is:

"3 times the product between two numbers, increased by 7"

ii) x*y + (x + y)

The first part, x*y, can be written as:

"the product of two numbers"

where the two numbers are the number x and the number y.

After that, we add the sum of these two numbers, then the complete sentence can be:

"the product of two numbers, plus the sum of these two numbers"

8 0
3 years ago
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