2 years ago

Find the range of the relation below, then determine whether the relation is a function.

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

4 0

Answer:

Step-by-step explanation:

It is a function because it passes the vertical line test and Xs do not repeat, then count out the Y-values which are the range.

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Find the inverse function. f(x) = x - 5

vesna_86 [32]

Answer:

f^-1 (x) = x^2 + 5

Step-by-step explanation:

f(x) = √x - 5

replace x with y

x= √y - 5

solve for y,

x =√y-5

x^2 + 5

Answer -

f^-1(x) = x^2 + 5

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2 years ago

What is the value of a1 of the geometric series? Sigma-Summation Underscript n = 1 Overscript infinity EndScripts 12 (negative o

worty [1.4K]

Answer:

Step-by-step explanation:

The given geometric series is

$\sum_{n = 1}^{ \infty} 12( { - \frac{1}{9} })^{n - 1}$

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Recall that the explicit formula is

$a_{n} = 12( { - \frac{1}{9} })^{n - 1}$

To find the first term, we put n=1 to get:

$a_{1} = 12( { - \frac{1}{9} })^{1 - 1}$

This gives us:

$a_{1} = 12( { - \frac{1}{9} })^{0}$

$a_{1} = 12(1) = 12$

Therefore the first term is 12

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3 years ago

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What’s the correct answer for this ?

Ann [662]

Answer:

8/3

9/11

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2 years ago

Can someone help me with this please !!

pogonyaev

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Fill in missing numbers. 250÷20=25 ÷ ...

ololo11 [35]

It’d be 2
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3 years ago