Given that ABCD is a rhombus, what is the value of x?
1 answer:
Answer:
d
Step-by-step explanation:
We know that diagonals bisect angles of a rhombus, meaning that they split the angles of two equal parts, that opposite angles are equal, and that the angles of a quadrilateral, such as a rhombus, add up to 360 degrees.
Looking at the drawing I uploaded, and taking into account that diagonals bisect angles of a rhombus, we can say that angle x = y and z = 5x-18
Next, given that opposite angles are equal, we can say that angle B = angle D and angle A = angle C. Therefore,
A+B+C+D= 360 (as the angles of a quadrilateral add up to 360)
A + B + A + B = 360 (plugging in A for C and B for D)
2 ( A + B) = 360
A + B = 180
x + y + z + 5x - 18 = 180 (plugging x+y in for A, and z+5x-18 in for B, as x and y make up A and z and 5x-18 make up B)
x+x+5x-18+5x-18 = 180 (because x=y and z=5x-18)
2(x+5x-18) = 180
divide both sides by 2
x+5x-18=90
6x-18=90
add 18 to both sides
6x=108
divide both sides by 6
x = 18
You might be interested in
Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.
<h3>What is the hang time equation?</h3>The hang-time of the ball for a player of jump h is given by:
The expression can be simplified as:
For a player that has a hang time of 0.9s, the jump is found as follows:
h = 3.24 feet.
For a player that has a hang time of 0.8s, the jump is found as follows:
h = 2.56 feet.
The difference is given by:
3.24 - 2.56 = 0.68 feet.
More can be learned about equations at brainly.com/question/25537936
#SPJ1