Answer:
1:3
Step-by-step explanation:
3/3=1
9/3=6
Answer:
Yes por dentro desta resposta concluímos que sim é vdd
<span>Give that </span>t<span>he frequency of G5 is 783.99 Hz.
To find the frequency of the note that is a perfect fifth above G5, we recall that </span>the frequencies of notes that are a 'perfect'
fifth apart are in the ratio of 1.5
i.e. <span>the frequency of the note that is a perfect fifth above G5 divided by </span><span>t<span>he frequency of G5 equal 1.5
Let the </span></span><span><span>frequency of the note that is a perfect fifth above G5 be F, then
F / </span>783.99 = 1.5
F = 1.5 x 783.99 = 1175.99
Therefore, </span>the <span>frequency of the note that is a perfect fifth above G5</span> is 1175.99 Hz
12+5c=c+4
4c=-8
C=-2
Please brainiest and like
Answer:
-6
Step-by-step explanation:
m=y2-y1/x2-x1
-54-(-30)=(-24)
11-7=4
-24/4=(-6)
hope this helps :3
if it did pls mark brainliest