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ser-zykov [4K]
3 years ago
13

Assign two variables for each problem, and write the equations. Do not solve.

Mathematics
1 answer:
NemiM [27]3 years ago
6 0
Price of boots is represented as x, price of tennis shoes is represented as y. x-y=44.38 x+y=196.12 Isolate x. (Or y, if you wanted to) x=y+44.38 x=196.12-y Set them equal to each other. y+44.38=196.12-y Solve for y. Then plug it in to either of the two original equations to find x. x=120.24 y=75.86 Note: This is assuming that the boots are more expensive than the tennis shoes. If the tennis shoes are more expensive than the boots, then the prices would be switched. I didn't find this clear in your question.
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Somebody help me please because i’m stuck
worty [1.4K]

The question is asking for you to plug in each number in the brackets into x and solve for y, or f(x), g(x), etc. I will do no. 19 as an example:

f(x) = -3x + 1

This problem has the domains -2, -1, and 0. First, we'll start with -2:

f(x) = -3(-2) + 1

f(x) = 6 + 1

f(x) = 7

Now -1:

f(x) = -3(-1) + 1

f(x) = 3 + 1

f(x) = 4

Lastly, 0:

f(x) = -3(0) + 1

f(x) = 0 + 1

f(x) = 1

For question 23, we can use the distance formula, which is ratextime. The domain in this case is time (t). You can set up a function like this: d(t) = 60t

8 0
3 years ago
What Is The Area Of The Rectangle: 145, 187. I AM COMPLETELY DESPRATE
Masteriza [31]

Answer:

27115

Step-by-step explanation:

145 x 187 = 27115

7 0
2 years ago
Find the area of the shaded region.
Iteru [2.4K]
Keeping in mind that the area of a rectangle is simply width * length, if we get the area of the larger rectangle, and then subtract the area of the smaller rectangle, we're in effect making a hole in the larger rectangle's area and thus what's leftover is the shaded area.

\bf \stackrel{\textit{area of the larger rectangle}}{(2x+2)(3x-4)}~~-~~\stackrel{\textit{area of the smaller rectangle}}{(x-3)(x-6)}
\\\\\\
\stackrel{FOIL}{6x^2-2x-8}~~~~-\stackrel{FOIL}{(x^2-9x+18)}\implies 6x^2-2x-8-x^2+9x-18
\\\\\\
5x^2+7x-26
4 0
3 years ago
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
An ant can crawl 3/4 of a yard in 1/2 minute. How long will it take for the ant to crawl 12 yards?​
Elan Coil [88]

Answer:

6 mins

Step-by-step explanation:

An ant can crawl 3/4 of a yard in 1/2 minute. How long will it take for the ant to crawl 12 yards?​

Ant crawls 3/4 of a yard in = 1/2 min = 60/2 sec = 30 sec

Ant crawls 12 yards in = 12 * 30 = 360 sec = 360/60 = 6 minutes

5 0
3 years ago
Read 2 more answers
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