What is 76+80000000000000000????? I need to know
Based on the calculations, all of the numbers belong to this arithmetic sequence.
<h3>How to calculate an arithmetic sequence?</h3>
Mathematically, the nth term of an arithmetic sequence can be calculated by using this expression:

<u>Where:</u>
- d is the common difference.
- a₁ is the first term of an arithmetic sequence.
- n is the total number of terms.
Next, we would determine the common difference as follows:
d = a₂ - a₁
d = 105 - 99 = 6.
d = a₃ - a₂
d = 111 - 105 = 6.
d = a₄ - a₃
d = 117 - 111 = 6.
Based on the calculations, all of the numbers belong to this arithmetic sequence.
Read more on arithmetic sequence here: brainly.com/question/12630565
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Complete Question:
What is the number that does not belong to this sequence 99, 105, 111, 117, 123, 129, 135, 141, 147, 153
Add 9 because -2 to 7 equals 9 hope this helped
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).