Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
To learn more on velocities: brainly.com/question/18084516
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Angles 1 and 3, angles 2 and 4, angles 5 and 7, and angles 6 and 8. They are also congruent, because vertical angles are congruent.
Answer:
(-2, -1).
Step-by-step explanation:
y = x² + 4x + 3
Completing the square:
y = (x + 4/2)^2 - (4/2)^2 + 3
y = (x + 2)^2 - 4 + 3
y = (x + 2)^2 - 1.
This is vertex form and the coordinates of the vertex are (-2, -1).
Option one because it’s going up by 50 and it’s also showing that she’s starting with the 200$ she already had