For the first problem, the answer is D, because every year, the graph goes down by about $4,500.
For problem two,
a. It's located in quadrant one because x and y are both positive (I've attached a graph with labeled quadrants for reference)
I'm unsure about b and c but I hope I helped with the others!
Line passing through point (-2, -3) with a slope of -6 is (y - (-3)) = -6(x - (-2)) => y + 3 = -6(x + 2)
Answer:
i'm confused is it asking what 64-28 is
Step-by-step explanation:
You'll be using point slope form to solve this.
As the name suggests, you'll need the slope as well as a point. To find the slope use the slope formula: 
Plug in the points.
The slope of this line is 5.
Point slope form is y-y1 = m(x-x1), so plug in the slope and a point into this equation. I'll use (0,8).
y-(8) = 5(x-(0))
1. Write this out without parentheses.
y-8 = 5(x)
2. Multiply 5 and x.
y-8 = 5x
3. Add 8 to both sides.
y = 5x+8
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Answer is:
y = 5x+8
Answer:
P(2) = 4
Step-by-step explanation:
P(X) = -2X4 + 4X3 - X + 6
Use the remainder theorem to find quotient and remainder and the value of P(2)
First add in any missing exponents: P(x) = -2x4 + 4x3 + 0x2 -x + 6
Write all the coefficients in a line (including the constant) with the number being solved for off to the left:
Bring down the first coefficient (-2), multiply it by the term in question (2), carry the product up under
the 2nd coefficient and then add down (4-4=0), carry up the sum and repeat process across. The last
sum is the answer for P(2)
(2) -2 4 0 -1 6
-4 0 0 -2
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-2 0 0 -1 4
P(2) = 4
check the answer: P(2) = -2(24) + 4(23) -2 + 6 = -2(16) +4(8) + 4 = 4 Our answer is correct
The quotient is what we would bet by dividing the original equation by the polynomial (x-2). The
answer is given by the bottom numbers which will begin an one lower exponent than the original.
Quotient is: -2x3 + 0x2 + 0x -1 = 2x3 - 1
The remainder is: 4/(x-2)
