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creativ13 [48]
3 years ago
10

A bowl contains 4 red marbles and 3 yellow marbles. Tim randomly draws 3 red marbles from the bowl. He replaces each marble afte

r it is drawn. What is the probability that he draws 2 yellow and 1 red?
Mathematics
1 answer:
mr Goodwill [35]3 years ago
6 0
So,

The probability of drawing a yellow marble is \frac{3}{7}.
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same: \frac{3}{7}.

The probability of drawing a red marble is \frac{4}{7}.

In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.

( \frac{3}{7} )( \frac{3}{7} )( \frac{4}{7} ) =  \frac{36}{343}

Because the order of the marbles doesn't matter, we will multiply the probability by 3.
3( \frac{36}{343} ) =  \frac{108}{343}
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