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3 years ago

In a standard deck of 52 playing cards, what is the complement (not below 8)?

Mathematics

1 answer:

Damm [24]3 years ago

8 0

Answer 2/13

Step-by-step explanation:

There are 52 cards in a standard deck: 13 ordinal cards (Ace -10, jack, Queen, King)and 4 of them

- one to each sute (hearts, diamonds, clubs, spades ) and so we have 4x13=52

There are 8 card that fit the question (4 each of access and kings).

so if you in a random draw the odds of drawing one of those 8 card out of the total number of 52 is 8/52

which we simplify

8/2=2/13

You might be interested in

What is 13.026 in expanded form using fractions for the decimal places

Crank

10 + 3 + 2/100 + 6/1000

hope it helps!

3 0

4 years ago

Read 2 more answers

True or false <br> all prime numbers are odd <br> i said false is that correct

Mumz [18]

False

2 is the only even prime number, the rest of the prime numbers are odd.

8 0

4 years ago

form a polynomial function whose real zeros are -2 with multiplicity 2 and 4 with multiplicity 1 whose degree is 3

NeTakaya

Answer:

$f(x) = {x}^{3} -12x - 16$

Step-by-step explanation:

We want to for a polynomial function whose real zeros are -2 with multiplicity 2 and 4 with multiplicity 1.

If -2 is a zero of a polynomial, then by the factor theorem, x+2 is a factor.

Since -2 has multiplicity 2, (x+2)² is a factor.

Also 4 is a zero which means x-4 is a factor.

We write the polynomial in factored form as:

$f(x) = {(x + 2)}^{2} (x - 4)$

We expand to get:

$f(x) = ({x}^{2} + 4x + 4)(x - 4)$

We expand further to get:

$f(x)=x({x}^{2} + 4x + 4) - 4({x}^{2} + 2x + 4)$

$f(x) = {x}^{3} + 4 {x}^2 + 4x - 4 {x}^{2} + 8x - 16$

$f(x) = {x}^{3} - 12x - 16$

4 0

3 years ago

In a prior sample of U.S. adults, the Center for Disease Control (CDC), found that 8% of the people in this sample had pinworm b

kow [346]

Answer: a) 453 b) 1537

Step-by-step explanation:

As per given , we have

Margin of error : E= 0.025

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

a) The prior estimate of population proportion : p=0.08

Required sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.08(1-0.08)(\dfrac{1.96}{0.025})^2\\\\=452.386816\approx453$

The minimum sample size is 453 U.S. adults.

b) Since the prior estimate of population proportion is not available , so we take p= 0.5

Required sample size :-

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.025})^2\\\\=1536.64\approx1537$

The minimum sample size is 1537 U.S. adults.

5 0

4 years ago

Part two out of six plz

podryga [215]

Factors of 24:
1,2,3,4,6,8,12,24

factors of 84:
1,2,3,4,6,7,12,14,21,28,42

highest common factor of 24 and 84:
12

Hope this helps!

6 0

3 years ago