Answer:
x + 1, y + 1
Step-by-step explanation:
For every x there is a y
(っ◔◡◔)っ ♥ Hope It Helps ♥
First, square both sides. This will cancel out the radical.

(a^2 = b + 6)
Then subtract 6 from both sides
b = a^2 - 6
Answer:
Part 1) The expression for the perimeter is
or 
Part 2) The perimeter when z = 15 ft. is 
Step-by-step explanation:
Part 1)
we have

Find the roots of the quadratic equation
Equate the equation to zero

Complete the square
Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient


Complete the square. Remember to balance the equation by adding the same constants to each side


Rewrite as perfect squares

-----> root with multiplicity 2
so
The area is equal to
![A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}](https://tex.z-dn.net/?f=A%3D625%28z-0.12%29%28z-0.12%29%3D%5B25%28z-0.12%29%5D%5B25%28z-0.12%29%5D%3D%2825z-3%29%5E%7B2%7D)
The length side of the square is 
therefore
The perimeter is equal to



Part 2) Find the perimeter when z = 15 ft.
we have

substitute the value of z

Answer:
Please find pdf
Step-by-step explanation:
Answer:


Step-by-step explanation:
Look at both terms separately, and isolate each "part."
i.e. 12x^4y^2 becomes 12, x^4, y^2
So the problem becomes:
12, x^4, y^2 and
30, x^3, y^1
Then, find the GCF of each term,
30 and 12 - 6
x^4 and x^3 - x^3
y^2 and y^1 - y^1
Hope it helps :) and let me know if you want me to elaborate.