X| 1 | 15 | 225 |
y| 4 | ? | 900 |
![\dfrac{y}{x}=const.](https://tex.z-dn.net/?f=%5Cdfrac%7By%7D%7Bx%7D%3Dconst.)
therefore
[tex]\dfrac{4}{1}=4;\ \dfrac{900}{225}=4;\ \dfrac{?}{15}=4\to?=60[\tex]
Answer: ? = 60
Answer:(X+Y)²
X²+Y² would be greater than X²-Y² since addition gives a greater result than subtraction.
X²+Y² would be greater than 2(X+Y); this is because 2(X+Y) = 2X+2Y, which will be less than X²+Y², since X>Y.
(X+Y)² = (X+Y)(X+Y). This can be simplified using the distributive property:
X(X)+X(Y)+Y(X)+Y(Y) = X²+XY+YX+Y² = X²+2XY+Y². This is greater than X²+Y².
A geometric sequence can always be expressed as:
a(n)=ar^(n-1), a=initial value, r=common ratio, n=term number
We are told that a(5)=25 and r=5 so we can say:
25=a5^(5-1)
25=a5^4
25=625a
a=1/25 so now we know our explicit formula for this geometric sequence:
a(n)=(1/25)(5^(n-1)) and the first three terms will be a(1), a(2), and a(3)
1/25, 1/5, 1
<span><span>27≤7x+6</span> </span>
to solve for x you'll have to subtract 6 from both sides then divide both sides by 7
<span><span>21≤7x</span></span>
<span><span /></span>
<span><span><span>3≤x</span> </span></span>