Answer: 0.6827
Step-by-step explanation:
Given : Mean IQ score : 
Standard deviation : 
We assume that adults have IQ scores that are normally distributed .
Let x be the random variable that represents the IQ score of adults .
z-score : 
For x= 90

For x= 120

By using the standard normal distribution table , we have
The p-value : 

Hence, the probability that a randomly selected adult has an IQ between 90 and 120 =0.6827
Answer:
I believe it is 157.813%
Step-by-step explanation:
Y=2x2-3
y=4-3
y=1
Hope this helps :)