<span>H(t) = −16t^2 + vt + s
</span>
<span>H(t) = −16t^2 + 100t + 140
H(t) = 0 = </span><span>−16t^2 + 100t + 140
16t^2 - 100t -140 = 0
t = [100 +/- √ (100^2 -4(16)(-140) ) ] /(2(16))
t = 7.43 and t = - 1.18.
El que tiene sentido para la pregunta es t = 7.43 s.
Option B) 7 s (approximately)
</span>
P a p a party party p q p w party
Answer:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula given by:

We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (<em>x₁, y₁</em>) and let B(4, -1) be (<em>x₂, y₂</em>). Substitute:

Evaluate:

So:

The distance between A(-8, 4) and B(4, -1) is 13 units.
Do you have a picture of the whole question?
D because that is the mean