Answer:
neutral, acidic, basic
Explanation:
Know the acidity rules. Sorry I just saw this!
- Hope that helps! Please let me know if you need further explanation.
Answer:
[NH₄NO₃] at D → 0.279 M
Explanation:
This exercise involves a series of dilutions one after the other.
First of all, we calcualte ammonium nitrate's concentration at A.
15.71 g . 1 mol/ 80 g = 0.196 mol / 0.150 mL = 1.31 M
At B → 1.31 M . 20 mL/ 75 mL = 0.349 M
At C → 0.349 M . 15 mL / 25 mL = 0.209 M
[NH₄NO₃] at B = 0.349 M
[NH₄NO₃] at C = 0.209 M
So let's calculate the new moles
In 1 mL of B we have 0.349 mmoles
In 10 mL of B we have 3.49 mmoles
In 1 mL of C we have 0.209 mmoles
In 10 mL of C we have 2.09 mmoles
Volume of D = 10 ml + 10ml = 20 mL
Total mmmoles = 3.49 mmoles + 2.09 mmoles = 5.58 mmoles
[NH₄NO₃] at D = 5.58 mmoles / 20mL → 0.279 M
Answer:
We have 1.69 moles of gas inside the balloon
Explanation:
Step 1: Data given
Volume of the balloon = 18.9 L
Temperature = 27.1 °C = 300.25 K
Pressure in the balloon = 2.20 atm
Step 2: Calculate the number of moles
p*V = n*R*T
n= (p*V)/(R*T)
⇒with n = the number of moles of gas
⇒with p = the pressure of gas = 2.20 atm
⇒with V = the volume of the gas = 18.9 L
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 27.1 °C = 300.25 K
n = (2.20 * 18.9) / ( 0.08206*300.25)
n = 1.69moles
We have 1.69 moles of gas inside the balloon
I think B
STEP-by STEP EXPLANATION