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ollegr [7]
3 years ago
5

NEED HELP FAST!!! THANKS

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

F(x) < 0 , over the intervals (-∞, -0.7) and (0.76 , 2.5)

Step-by-step explanation:

The correct answer is the first option

F(x) < 0 , over the intervals (-∞, -0.7) and (0.76 , 2.5)

We can see that over those intervals, the function becomes negative.

That is, it becomes less than zero.

We can see the graph in the image below.

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Which answer describes the restrictions for the variables x+1/x-4?
MakcuM [25]
The restriction for this is that x ≠ 4. This is because 4 - 4 = 0, and you cannot divide by zero.

An alternative way of writing this (interval notation) is (-∞, 4)U(4, <span>∞).

Hope this helps!</span>
5 0
3 years ago
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A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per
gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is \dfrac{dx}{dt}= Rate \ of \  \ inflow - rate \ of \  \ outflow

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank  × flow rate

= x/250 ×  9

= 9x/250  lb/s

∴

\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}

\dfrac{dx}{dt} + \dfrac{9x}{250}= 21

This is a 1st order linear differentiation,

The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

∴

e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

Hence;

100 = \dfrac{1750}{3}+C

C = \dfrac{1750}{3} -100

C = - \dfrac{1450}{3}

∴x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}

after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}

x(t) = 581.66 lb

5 0
4 years ago
Evaluate the function at the fiven values of the variables:
Arlecino [84]

Answer:

f(-3)=5x^2+5x*3

-f*3=5x^2+5*3x

-3f=5x^2+15x

f=-5x(x+3)/3

f(-9)=5x^2+5x*3

-f*9=5x^2+5*3x

-9f=5x^2+15x

f=-5x(x+3)/9

Step-by-step explanation:

hope it helps you?

4 0
4 years ago
How many terms are in this expression 3x2y4z − 6xy − 3z(5x2)
Liono4ka [1.6K]

Answer:C 3 Term

Step-by-step explanation:

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4 years ago
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What is a solution of the inequality shown below? -6 + b ≥ -6​
KiRa [710]

Answer:

Solution given;

-6 + b ≥ -6

adding 6 on both side

-6+6+b≥-6+6

<u>b</u><u>≥</u><u>0</u>

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3 years ago
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