The restriction for this is that x ≠ 4. This is because 4 - 4 = 0, and you cannot divide by zero.
An alternative way of writing this (interval notation) is (-∞, 4)U(4, <span>∞).
Hope this helps!</span>
Answer:
x(t) = 581.66 lb
Step-by-step explanation:
From the given information:
Consider the salt quantity in the tank at time t be x(t) lb.
∴ the rate of change of salt content in the tank is 
where:
the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons
=21 lb/s
rate of outflow = salt conc. in the tank × flow rate
= x/250 × 9
= 9x/250 lb/s
∴


This is a 1st order linear differentiation,
The integrating factor if 
∴


at t = (0) and x(0) = 100 lb
Hence;



∴
after time t = 1 minute i.e 60 s


x(t) = 581.66 lb
Answer:
f(-3)=5x^2+5x*3
-f*3=5x^2+5*3x
-3f=5x^2+15x
f=-5x(x+3)/3
f(-9)=5x^2+5x*3
-f*9=5x^2+5*3x
-9f=5x^2+15x
f=-5x(x+3)/9
Step-by-step explanation:
hope it helps you?
Answer:C 3 Term
Step-by-step explanation: