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marin [14]
4 years ago
12

A park is shaped like a rectangle with a length 5 times its width (w). What is a simplified expression for the distance between

opposite corners of the park?
Mathematics
1 answer:
inna [77]4 years ago
7 0

Answer:

w√26

Step-by-step explanation:

A rectangle is a four sided shape with 4 perpendicular angles. It has two pairs of parallel sides which are equal in distance: width and length. The width here is w and the length is 5w or 5 times the width. A diagonal can be drawn between opposite corners that splits the triangle into two equal right triangles. The distance of this diagonal is found using the Pythagorean Theorem a² + b² = c². In the rectangle a = w and b = 5w. Substitute these values and simplify using a square root operation.

w² + (5w)² = c²

w² + 25w² = c²

26w² = c²

√26w² = c

w√26 = c

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Find the maximum and minimum values attained by the function f along the path c(t). (a) f(x, y) = xy; c(t) = (cos(t), sin(t)); 0
goblinko [34]

Answer:

a) Therefore, the minimum value of the function f is -1/2.

Therefore, the maximum value of the function f is 1/2.

b)Therefore, the minimum value of the function f is 1.

Therefore, the maximum value of the function f is 16.

Step-by-step explanation:

We find the maximum and minimum values attained by the function f along the path c(t). From exercise we have:

a)

f(x,y)=xy\\\\c(t)=(\cos t, \sin t)\\\\\0\leq t\leq 2\pi\\  

Therefore, we get:

f(x,y)=xy\\\\f(x,y)=\cos t \cdot \sin t\\\\f(x,y)=\frac{1}{2} \sin 2t

We know that:

-1\leq \sin 2t\leq 1\\\\\implies -\frac{1}{2} \leq \frac{1}{2}\sin 2t\leq \frac{1}{2}\\\\\implies -\frac{1}{2}\leq f(x, y)\leq \frac{1}{2}

Therefore, the minimum value of the function f is -1/2.

Therefore, the maximum value of the function f is 1/2.

We use software to drawn a graph.

b)

f(x,y)=x^2+y^2\\\\c(t)=(\cos t, 4\sin t)\\\\0\leq t\leq 2\pi\\

Therefore, we get:

f(x,y)=x^2+y^2\\\\f(x,y)=(\cos t)^2 \cdot (4\sin t)^2\\\\f(x,y)=\cos^2t+16\sin^2t\\\\f(x,y)=\cos^2t+\sin^2t+15\sin^2t\\\\f(x,y)=1+15\sin^2t

We know that:

0\leq \sin^2t\leq 1\\\\\implies 0\leq 15\sin^2t\leq 15\\\\1\leq 1+15\sin^2t\leq 16\\\\ \implies 1\leq f(x,y) \leq 16

Therefore, the minimum value of the function f is 1.

Therefore, the maximum value of the function f is 16.

We use software to drawn a graph.

3 0
3 years ago
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GalinKa [24]
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4 years ago
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What is the answer to -x-(-10x) work
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Answer:

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