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Mariana [72]
4 years ago
14

ETHANHUNT HELP PLS NOBODY ELSE DONT ANSWER I DONT TRUST U PEOPLE

Mathematics
2 answers:
notsponge [240]4 years ago
6 0
A regular polygon<span> is a </span>polygon <span>that is equiangular (all angles are equal in measure) and equilateral (all sides have the same length).

Here, Figure C is an equilateral Triangle which fits the most.

In short, Your Answer would be Option C

Hope this helps!</span>
lubasha [3.4K]4 years ago
4 0
The answer is Figure C. Lol I just answered a question just like this! :)
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The y-intercept of the graph of y=(x-c)(x-d)^3 is
snow_lady [41]

Answer:

Just Make x=0

y_i=(-c)(-d)^3=cd^3

6 0
3 years ago
Daily highs in Sacramento for the past week were:
lidiya [134]

Answer:

Answer: 91.7 = .6 (92) + .3 (90) + .1(95

Step-by-step explanation:

Answer: 91.7 = .6 (92) + .3 (90) + .1(95

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5 0
3 years ago
A+b/a-b=5/3 what are the following ratios? 3a:2b
Papessa [141]

Answer:

3 a : 2 b = 6 : 1

Step-by-step explanation:

<em>\frac{a + b}{a - b} = \frac{5}{3}</em>

<em>3 ( a + b) = 5 ( a - b) </em>

<em>3 a + 3 b = 5 a - 5 b </em>

<em>5 b + 3 b = 5 a - 3 a </em>

<em> 8 b = 2 a </em>

<em> 2 a = 8 b</em>

<em><u>a = 4 b</u></em>

<em>3 a = 3 × 4 b</em>

<em><u>3 a = 12 b</u></em>

<em>3 a: 2 b = 12 b : 2 b</em>

<em>3 a : 2 b = 6 : 1</em>

7 0
4 years ago
Read 2 more answers
Plz help !!
Citrus2011 [14]

If your teacher/book requires a standard form for the equation of a line, don't forget to convert the equations into them!

6 0
3 years ago
2) Here are two relations defined on the set {a, b, c, d): S= { (a, b), (a, c), (c, d), (c, a)} R={ (b, c), (c, b), (a, d), (d,
Dovator [93]

Answer:

Given relations defined on the set {a, b, c, d},

S= { (a, b), (a, c), (c, d), (c, a)}

R={ (b, c), (c, b), (a, d), (d, b)},

Since, SoR(x) = S(R(x)),

So, SoR(a) = S(R(a)) = S(d) = ∅,

SoR(b) = S(R(b)) = S(c) = d and a,

SoR(c) = S(R(c)) = S(b) = ∅,

SoR(d) = S(R(d)) = S(b) = ∅,

Thus, SoR = { (b,d), (b,a) }

RoS(a) = R(S(a)) = R(b) = c and RoS(a) = R(S(a)) = R(c) = b,

RoS(b) = R(S(b)) = R(∅) = ∅,

RoS(c) = R(S(c)) = R(d) = b and RoS(c) = R(S(c)) = R(a) = d

RoS(d) = R(S(d)) = R(∅) = ∅,

Thus, RoS = { (a, c), (a, b), (c,d), (c, b) },

SoS(a) = S(S(a)) = S(b) = ∅ and SoS(a) = S(S(a)) = S(c) = d and a

SoS(b) = S(S(b)) = S(∅) = ∅,

SoS(c) = S(S(c)) = S(d) = ∅ and SoS(c) = S(S(c)) = S(a) = b and c

SoS(d) = S(S(d)) = S(∅) = ∅,

SoS = { (a, d), (a, a), (c, b), (c, c) }

7 0
3 years ago
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