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aleksklad [387]
3 years ago
9

For what values of b are the given vectors orthogonal? (−30, b, 5), (b, b2, b)

Mathematics
1 answer:
mart [117]3 years ago
3 0

Given :

Two vectors :

v_1=-30i+bj+5k\\\\v_2=bi+2bj+bk\\\\

To Find :

The value of b for which the vectors are orthogonal .

Solution :

We know , two vectors are orthogonal when the are perpendicular to each other .

So , their dot product will be zero .

So ,

-30b+2b^2+5b=0\\\\2b^2-25b=0\\\\b(2b-25)=0

Therefore , for b =0 and b=\dfrac{25}{2} the vectors are orthogonal .

Hence , this is the required solution .

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Answer:

The number of 57-cent stamps that Julie bought is 12

Step-by-step explanation:

Given equation

0.57 s + 0.3 ( s − 6 ) = 8.64

Open bracket

0.57s + 0.3s - 1.8 = 8.64

Collect like terms

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Divide both sides by 0.87

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Answer:

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Step-by-step explanation:

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Are 2/3 and 6/8 equivalent?
miskamm [114]
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Find the equation of the line that is perpendicular to y = – 1 4 x – 8 and passes though the point (2, –4).
vivado [14]

The equation of the line is y=\frac{1}{4}x-\frac{29}{7}

Explanation:

The equation of the line is perpendicular to y=-14 x-8

The equation is of the form y=mx+b where m=-14

<u>Slope:</u>

The slope of the perpendicular line can be determined using the formula,

m_1 \cdot m_2=-1

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Thus, the slope of the line is m=\frac{1}{14}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the slope m=\frac{1}{14} and the point (2,-4), we get,

y+4=\frac{1}{14}(x-2)

Simplifying, we get,

y+4=\frac{1}{14}x-\frac{1}{7}

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Thus, the equation of the line is y=\frac{1}{4}x-\frac{29}{7}

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Select all the statements that describe the expression 5+2x.
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Answer:

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