Answer:
2 and 6, 1 and 5
Step-by-step explanation:
Answer:
x = 0, y = 1
Step-by-step explanation:
2x + 6y = 6 → (1)
x - 3y = - 3 ( add 3y to both sides )
x = 3y - 3 → (2)
substitute x = 3y - 3 into (1)
2(3y - 3) + 6y = 6 ← distribute parenthesis and simplify left side
6y - 6 + 6y = 6
12y - 6 = 6 ( add 6 to both sides )
12y = 12 ( divide both sides by 12 )
y = 1
substitute y = 1 into (2)
x = 3(1) - 3 = 3 - 3 = 0
solution is x = 0 , y = 1
Log 2 200 = In 200 ã• In 2 = 7.6... â need 8 bits. If a signed number is being stored, then 9 bits would be needed as one as one would be needed to indicate the sign of the number.
8 (assuming unsigned numbers - i.e., you don’t reserve a bit for the sign.
Answer:p+3
Step-by-step explanation:
12+3=15
Therefore the expression =p+3
This is a real tricky question. There are a lot of primes that fit this description.
3 5 7 9 (does't work. It's prime factors are the same).
11 13 17 19
I think the answer you want is 15, but it depends on what you have been told about 1. Is 1 prime or not?
