All categories

3 years ago

At the store 8 batterys cost 10 dollars,how much do 6 battery cost

Mathematics

1 answer:

scZoUnD [109]3 years ago

6 0

8batterys=$10

6batterys=x

to determine the cost of 6 battery, we have to determine the cost of one battery

1=10/8

=1.25

6battery=6*1.25

x=7.5

You might be interested in

How to graph Y > x- 4

victus00 [196]

Answer:

You should probably use a website called desmos if u ever need to graph somethin

Step-by-step explanation:

3 0

3 years ago

PLZ dont ignore me! I need help on this :(

Illusion [34]

Answer: should be the last answer! to the right.

Step-by-step explanation:

You have 30 coins and the d are dimes and q are quarters

6 0

3 years ago

What is the sum of the first 51 terms of the sequence?<br><br> −282,−266,−250,−234,...

Pavel [41]

Answer:

The sum of the first 51 terms of the sequence is 6018

Step-by-step explanation:

AP: −282,−266,−250,−234,...

First term = a = -282

Common difference = d = $a_2-a_1=a_3-a_2$

Common difference = d = -266-(-282)=-250-(-266)=16

Formula of sum of first n terms = $S_n=\frac{n}{2}(2a+(n-1)d)$

Substitute n = 51

So, $S_{51}=\frac{51}{2}(2(-282)+(51-1)(16))$

$S_{51}=6018$

Hence the sum of the first 51 terms of the sequence is 6018

8 0

3 years ago

Plz Help!! With 5,6,7,8

strojnjashka [21]

6 is 9.088 because it said it for u

8 0

4 years ago

1. Which are true of x = log10 31,500? Select all that apply.

ziro4ka [17]

Given:

$x=\log_{10}31,500$

To find:

Select the true statements from the given options about the given value.

Solution:

We have,

$x=\log_{10}31,500$

It can be written as

$x=\log_{10}(2^23^25^37)$

$x=\log_{10}(2^2)+\log_{10}(3^2)+\log_{10}(5^3)+\log_{10}(7)$ $[\because \log(ab)=\log a+\log b]$

$x=2\log_{10}2+2\log_{10}3+3\log_{10}5+\log_{10}(7)$

$x=2\left(0.30105\right)+2\left(0.47712\right)+3\left(0.69897\right)+0.8451$

$x=4.49835$

Clearly, the value of x lies between 4 and 5. So, $x>4$ and $x$ .

Therefore, the correct options are C and D.

4 0

3 years ago