1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexandra [31]
3 years ago
9

Every econimics desicion has

Chemistry
1 answer:
ASHA 777 [7]3 years ago
8 0

Every Economic decision has : Gained opportunities.

You might be interested in
Name the bonds found between amino acids in a polypeptide chain
Anon25 [30]

Answer:

Explanation:

dunno

3 0
3 years ago
G the normal range of the ph of blood is between 7.35 and 7.45; variations beyond this range have significant health implication
Fiesta28 [93]

Answer : the hydrogen ion concentrations for pH = 7.35 and pH = 7.45 are 4.46 x 10⁻⁸ M and 3.54 x 10⁻⁸ M respectively.

When the pH of a solution is less than 7, the hydrogen ion concentration is higher and therefore the solution is acidic.

On the other hand, when the pH of a solution is greater than 7, hydroxide ion concentration is higher and the solution acts as a base.

The normal pH range of blood is given as 7.35 - 7.45  which is greater than 7. That means blood is slight basic in nature.

Let us find hydroxide ion concentration of blood.

pH + pOH = 14

7.35 + pOH = 14

pOH = 6.65

pOH = - log [OH-]

[OH-] = 10^{-6.65}

[OH-] = 2.24 \times 10^{-7}

Ionic product of water is written as,

[H+] [OH-] = 1 \times 10^{-14}

Let us plug in the calculated value of [OH-]

[H+] = \frac{1 \times 10^{-14}}{2.24 \times 10^-7} = 4.46 \times 10^{-8} M

The hydrogen ion concentration for pH = 7.35 is 4.46 x 10⁻⁸ M

Calculation of [H+] for pH = 7.45

pOH = 6.55

[OH-] = 2.82 x 10⁻⁷

[H+] = \frac{1 \times 10^{-14}}{2.82 \times 10^-7} = 3.54 \times 10^{-8} M

Similarly, for pH = 7.45, we get hydrogen ion concentration of 3.54 x 10⁻⁸ M.

8 0
4 years ago
can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ
mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

7.SL

8.CL

9.SL

10.CL

Explanation:

HOPE ITS HELP

5 0
3 years ago
In a chemical reaction represented by the general equation A+ B = C + D, there are 4 distinct mole ratios that can be written. T
nydimaria [60]

So,

These species react stoichiometrically.  Thus, we can say, for example, that 1 mol A is stoichiometrically equivalent to 1 mol B in this reaction.  I will say A = B.

A = B

A = C

A = D

B = C

B = D

C = D

As you can see, there are more than 4 distinct mole ratios for this reaction.  Thus, the statement is false.

6 0
4 years ago
Read 2 more answers
I NEED HELP ASAP! :)
cluponka [151]

Answer:

When adding the measurements 42.1014g + 190.5g, the answer has<u> </u><u>seven </u>significant figures.

When dividing the measurements 400g/32.2 cm^3, the answer has <u>ten</u> significant figures.

Explanation:

7 0
3 years ago
Other questions:
  • If you were to take the universe's temperature, what would the reading be ?
    13·1 answer
  • True or false? the normal boiling point of water is 100oc, which is a physical property of the substance water
    12·1 answer
  • Ocean waves are caused by
    15·1 answer
  • Hydrogen and nitrogen react to form ammonia according to the reaction,
    15·2 answers
  • Define duplet and octet??​
    6·1 answer
  • You are given a small bar of an unknown metal. You find the density of the metal to be 10.5 g/cm3. An X-ray diffraction experime
    8·2 answers
  • Does anyone know the answer!??​
    13·1 answer
  • Classify these bonds as ionic, polar covalent, or covalent, and give your reasons: (a) the SiSi bond in Cl3SiSiCl3, (b) the SiCl
    12·1 answer
  • Use the fact that to determine how much the pressure must change in order to lower the boiling point of water by a small amount
    15·1 answer
  • How did dalton advance the atomic philosophy proposed by democritus
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!