<u>Answer:</u> The number of 
ions dissociated are 
<u>Explanation:</u>
We are given:
pH = 2.07
Calculating the value of pOH by using equation, we get:
To calculate hydroxide ion concentration, we use the equation to calculate pOH of the solution, which is:
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
We are given:
pOH = 11.93
Putting values in above equation, we get:
![11.93=-\log[OH^-]](https://tex.z-dn.net/?f=11.93%3D-%5Clog%5BOH%5E-%5D)
![[OH^-]=10^{-11.93}=1.17\times 10^{-12}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D10%5E%7B-11.93%7D%3D1.17%5Ctimes%2010%5E%7B-12%7DM)
To calculate the number of moles for given molarity, we use the equation:
Molarity of solution = 
Volume of solution = 1243 mL = 1.243 L (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
According to mole concept:
1 mole of a compound contains 
number of particles
So, 
number of will contain = 
number of ions
Hence, the number of ions dissociated are
Answer:
an increase of acceleration or decrease of acceleration
Explanation:
Answer:
94.1 %
Explanation:
We firstly determine the equation:
2H₂O + O₂ → 2H₂O₂
2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.
We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol
Certainly oxygen is the limiting reactant.
2 moles of water react to 1 mol of oxygen.
13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)
As we determine the limiting reactant we continue to the products:
1 mol of O₂ can produce 2 moles of H₂O₂
Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles
We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g
That's the 100% yield or it can be called theoretical yield.
Percent yield = (Yield produced / Theoretical yield) . 100
(100g / 106.25 g) . 100 = 94.1 %
.2135 mol of Ba(OH)2 are needed to neutralize .427 mol of 2HC2H3O2
