PH of acidic buffer = pKa + log [CH₃COONa - HCl] / [CH₃COOH + HCl]
pKa of CH₃COOH = 4.74
Concentration of acetic acid in buffer = 2.0 M
Concentration of sodium acetate = 1.0 M
Concentration of HCl must add = x
pH = 4.74 + log (1-x) / (2+x) = 4.11
x = concentration of HCl must be added = 0.43 M
number of moles of HCl = M * V = 0.43 * 1 = 0.43 mol
mass of HCl must be added = 0.43 * 36.5 = 15.7 g
well if i am not mistaken it is true. i just did the the class and yes its true i just looked back.
thanks for asking your question on brainly have a nice day:D
The reaction is shown below,
Step 1: Hydration of Alkene: In first step
Ethene is hydrated to Ethanol through
Hydroboration Reaction.
Step 2: Oxidation of Primary Alcohol: In this step partial oxidation of ethanol is carried out using mild Oxidizing agent <span>Pyridinium chlorochromate (
PCC) and Acetaldehyde is produced.
Step 3: Reduction of Acetaldehyde followed by Oxidation: In this step, first acetaldehyde is reduced to
secondary alcohol using
grignard reagent. After that the sec. alcohol is oxidized to
ketone by using oxidizing agent CrO</span>₃.
4.167 m/per second 250 m/per minute