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marissa [1.9K]
3 years ago
13

In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 59.3%. The differen

ce between the number of cars and the number of SUVs is 16. Find the number of SUVs in the lot.
Mathematics
1 answer:
frutty [35]3 years ago
4 0

Answer:

27 SUVs

Step-by-step explanation:

Let number of ordinary cars be x and SUVs be y

We can write 2 equations and use substitution to solve for the number of SUVs.

<u>"The number of ordinary cars is larger than the number of sport utility vehicles by 59.3%"- </u>

This means that 1.593 times more is ordinary cars (x) than SUVs (y), so we can write:

x  = 1.593y

<u>"The difference between the number of cars and the number of SUVs is 16" - </u>

Since we know ordinary cars are "more", we can say x - y = 16

<em>We can now plug in 1.593 y into x of the 2nd equation and solve for y:</em>

<em>x - y = 16</em>

<em>1.593y - y = 16</em>

<em>0.593y = 16</em>

<em>y = 27 (rounded)</em>

<em />

<em>Hence, there are 27 SUVs</em>

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qaws [65]

Answer:

202(7 )/(12 )

Step-by-step explanation:

5(4)/(6)*6(1)/(2)*5(1)/(2)=202(7 )/(12 )

Just remember V=l*w*h

5 0
3 years ago
Please help very easy!
Bingel [31]
A) the mode is greater than the median
tip: the mean will always be greater than everything
7 0
3 years ago
A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes
Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is \dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}

The area to be planted with flowers is approximately <u>923.558 m²</u>

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

A = \dfrac{7}{4} \cdot a^2 \cdot  cot \left (\dfrac{180 ^{\circ}}{7} \right )

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}

s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69

The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52

The area of the heptagon MNSRQPO is therefore;

A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94

MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times  21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08

By sine rule, we have

\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}

sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})

\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

Area \ of \Delta MSQ = \dfrac{1}{2}  \times  43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}

The area of the of the garden plated with flowers, A_{req}, is given as follows;

A_{req} = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

A_{req}= 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, A_{req} ≈ <u>923.558 m²</u>

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0
3 years ago
susan mountain elevation is 1530 meters. After 4 hours of climbing down to her elvationis 680 meters. What is susans avarge chan
iVinArrow [24]

Answer:

-850 is the answer

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
NEED HELP ON ALL OF THESE PLEASE
tangare [24]

Answer:

1) 2670m^2

2) 4718 in^2

3) 4730 ft^2

4) 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

Step-by-step explanation:

Area of a rectangular prism = 2wl + 2lh + 2hw

Where,

w = width

l = length

h = height

1) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 10m; l = 31m; w = 25m

Area = 2(25m)(31m) + 2(31m)(10m) + 2(10m)(25m)

= 2(775m^2) + 2(310m^2) + 2(250m^2)

= 1550m^2 + 620m^2 + 500m^2

= 2670m^2

2) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 21 in; l = 35 in; w = 29 in

Area = 2(29in)(35in) + 2(35in)(21in) + 2(21in)(29in)

= 2(1015in^2) + 2(735in^2) + 2(609in^2)

= 2030in^2 + 1470in^2 + 1218in^2

= 4718 in^2

3) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 19 ft; l = 39ft; w = 28ft

Area = 2(28ft)(39ft) + 2(39ft)(19ft) + 2(19ft)(28ft)

= 4730 ft^2

4) Area of a rectangular prism = 2wl + 2lh + 2hw

h = 24,cm; l = 49cm; w = 38cm

Area = 2(38cm)(49cm) + 2(49cm)(24cm) + 2(24cm)(38cm)

= 7900cm^2

5) 11 542mm^2

6) 3740m^2

7) 6374m^2

8) 2824 ft^2

9) 6004mm^2

Note : Kindly follow the same process for the remaining questions, you'd get their correct answers. I can't finish up due to time constraints. However, you may send me a direct message for the remaining answers. Thank you.

5 0
3 years ago
Read 2 more answers
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