Answer:
72 students
Step-by-step explanation:
IF 2 out of 3 students recycle aluminum cans and 48 students recycle aluminum cans.
48 divided by 2 is 24
48 plus 24 is 72
Answer:
A, B, D, E
Step-by-step explanation:
Answer:
I suppose maybe the catch is in interpreting the following sentence: "The values of these two amounts are modeled as constants that are unknown". I take it to mean that they're just two randomly and independently generated numbers.
Step-by-step explanation:
The answer given in the solution manual claims that this indeed helps, and that the probability of getting the better envelope is given by
p=1/2+1/2P(B)
where B is the event that a<X<b, with a,b being the smaller and larger amount of dollars, respectively.
I do not buy this solution for the following reason: tossing a coin has nothing to do with the contents of the envelopes. You do not gain any information by doing it. You could just as well count the amount of leaves on a nearby tree instead and use that for X.
Similarly, opening the first envelope also gives you no useful information about the ordering relation between a and b, so surely that's another red herring. Even if you forget the coin tossing, the probability of "winning" is still 1/2, swap or no swap.
1 Simplify exponent
ma2cr+acar+car+ar+r=vacar
2 Simplify exponent
ma2cr+a2cr+car+ar+r=vacar
3 Factor out the common term r
r(ma2c+a2c+ca+a+1)=vacar
4 Cancel r on both sides
ma2c+a2c+ca+a+1=vaca
5 Subtract a2c from both sides
ma2c+ca+a+1=vaca−a2c
6 Factor out the common term ca
ma2c+ca+a+1=ca(va−a)
7 Subtract ca from both sides
ma2c+a+1=ca(va−a)−ca
8 Factor out the common term ca
ma2c+a+1=ca(va−a−(1))
9 Subtract a from both sides
ma2c+1=ca(va−a−1)−a
10 Factor out the common term a
ma2c+1=a(c(va−a−1)−1)
11 Subtract 1 from both sides
ma2c=a(c(va−a−1)−1)−1
12 Divide both sides by a2
mc=a(c(va−a−1)−1)−1a2
13 Divide both sides by c
m=a(c(va−a−1)−1)−1a2c
