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Aleks04 [339]
3 years ago
11

Please help me ☣️☢️☢️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️⬅️▫️​

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

acute isosceles triangle

vertex angle, y =  44.0 degrees. (smallest angle)

Step-by-step explanation:

If the sides are in the ratio 4:4:3,

two of the sides have equal lengths, so it is an isosceles triangle.

Also, the sum of square of the two shorter sides is greater than the square of the longest side, so it is an acute triangle.

To find the smallest angle, we draw the perpendicular bisector of the base (side length 3) and form two right triangles.

The base angle x is given by the ratio

cos(x) = 1.5/4 = 3/8

Consequently the base angle is  arccos(3/8) = 68.0 degrees.

The vertex angle equals twice the complement of 68.0

vertex angle, y = 2 (90-68.0) = 44.0 degrees. (smallest angle)

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4 years ago
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makkiz [27]

Answer:<em> </em><em>a)</em> x=\dfrac{-9 \pm\sqrt{113} }{8}

             <em> b) x₁ = - 14; x₂ = 6.</em>

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a) 4x² + 9x - 2 = 0

x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=4; \: \: b=9; \: \: c=-2\\x =\dfrac{-9 \pm \sqrt{9^{2}-4 \cdot 4 \cdot (-2) } }{2 \cdot 4} =\dfrac{-9 \pm\sqrt{113} }{8}

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7 0
3 years ago
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