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madam [21]
3 years ago
13

Can you guys help me?​

Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

Step-by-step explanation:

1. y = 2x

       y = 2*4 = 8  Checks, therefore

y = 20  for x = 10

2. y = 3x

       y = 3*(0.3) = 0.9  Checks, therefore:

y =  3*(1.5) = 4.5  

       y = 3*

3. y = 5/x

       y = 5/(1/2) = 10  Checks, therefore:

       3 = 5/x

x = 5/3

4 v = wu

7*3 = 21  Checks, therefore:

v =  (3/4)*(6) = (18/4) = (9/2)

v = (2/3)wu

v = (2/3)*7*3 = 14 Checks

5 m = Kn/p  [Add the K as a constant that will make m = Knp true at some value of K]

9 = K*2/(1/3)

27 = (K*2)

27 = 2K

K = (3/2)

       m = (3/2) (n/p)

       m = (3/2)*((1/2)/(1/3))

        m = (3/2)*(3/2)

        m = 1

   

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If m<1 is 115 what is m<4​
aniked [119]

I'm not sure if this is right, but I multiplied 115 by 4 and got 460- Try that? ;^;

4 0
3 years ago
What is the value of x in the equation below?
Nutka1998 [239]

Answer:

B) x = -12

Step-by-step explanation:

[Given] -2.5(x-4) = -3x + 4

[Distibute] -2.5x + 10 = -3x + 4

[Subtract 4 from both sides] -2.5x + 6 = -3x

[Add 2.5x to both sides] 6 = -0.5x

[Divide both sides by -0.5] -12 = x

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

4 0
2 years ago
Read 2 more answers
Kevin Horn is the national sales manager for National Textbooks, Inc. He has a sales staff of 40 who visit college professors al
just olya [345]

Answer:

(a) median = 57

(b) Q1=50     Q3=63.5

(c)D1 = 41   D9=67

(d)P33= 51

Step-by-step explanation:

(a) The numbers are arranged in ascending order, and there are even number of calls. So the median will be the average of the middle terms.

middle terms are 55 and 59

Median = \frac{55+59}{2}

median= 57

(b) First quarter Q1 = \frac{1}{4} number of callsth

=\frac{1}{4} *30th

= 7.5th

so the first quarter lies in the 7.5th= (7+0.5)th term

So we multiply 0.5 by the difference of the 7th and 8th term

=0.5 *0= 0

Q1 = 50+0=50

Q3=\frac{3}{4} number of callsth

=\frac{3}{4} *30th

=22.5th = (22+0.5)th term

So we multiply 0.5 by the difference of the 22th and 23rd term

= 0.5*1=0.5

Q3= 63+0.5=63.5

(c) First decile (D1) = \frac{1}{10} number of callsth

=\frac{1}{10} *30th

= 3rd term

D1= 41

D9= \frac{9}{10} number of callsth

=\frac{9}{10} *30th

  =27th term

D9 = 67

(d) 33rd percentile =\frac{33}{100} number of callsth

=\frac{33}{100} *30th

= 9.9th term = (9 +0.9)th

Multiply 0.9 by the difference between the 9th and tenth term.

= 0.9*0 =0

P33 = 51

8 0
3 years ago
(20,-3) (19,-20) formula is: y2-y1/x2-x1
Orlov [11]

Answer:

17

Step-by-step explanation:

The first thing to do is plug in the numbers for the equation. Starting with:

[-20-(-3)]/(19-20)

When you answer that you simplify the answer to

(-20+3)/(19-20)

You answer what is in the parenthesis first.

(-17)/(-1)

After this step you simplify.

17.

The answer is seventeen because any number over 1 is just the number. For example, 3/1=3. The answer is positive because the negative in the numerator and denominator cancel eachother out. leaving the answer as 17.

6 0
3 years ago
Read 2 more answers
F(x)= |3x-4|+2, find f(-10)
Zarrin [17]
f(x)=|3x-4|+2 \\ \\
f(-10)=|3 \times (-10) -4|+2=|-30-4|+2=|-34|+2=34+2 \\ f(-10)=36
7 0
4 years ago
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