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2 years ago

Please say whether each one is y=1, y=2, or y=3

Mathematics

2 answers:

Bingel [31]2 years ago

8 0

Number 1-y=2
number 2-y=1
number 3-both y=2 and y=1

(might to be correct but pretty sure)

puteri [66]2 years ago

8 0

2y+5=9 : y=2
2y+5<9 : y<2 : y=1
2y+5<=9 : y=2 and y=1

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aivan3 [116]

<h3>Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$ </h3>

Step-by-step explanation:

$3x^2 +9x -6=0$ $x = \frac{-b\pm\sqrt{b^2- 4ac} }{2a}$

$\Leftrightarrow x = \frac{-9\pm\sqrt{9^2- 4.3(-6)} }{2.3}$ here a = 3 ,b = 9 and c= -6

$\Leftrightarrow x = \frac{-9\pm\sqrt{153} }{6}$

$\Leftrightarrow x = \frac{3(-3\pm\sqrt{17}) }{6}$

$\Leftrightarrow x = \frac{-3\pm\sqrt{17}}{2}$

Therefore either $x = \frac{-3+\sqrt{17}}{2}$ or, $x = \frac{-3-\sqrt{17}}{2}$

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Representative is paid the greater

vivado [14]

Building and solving an inequality, it is found that at a volume of sales of $11,875 he will start to earn more from the commission based compensation.

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We want to find how much in dollars he has to sell such that 8% of this amount is greater than $950.
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A similar problem is given at brainly.com/question/17248342

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