Answer:
Step-by-step explanation:
let one diagonal=x
other diagonal=3x
area=1/2 (x±3x)=3/2 x²=54
x²=54×3/2=81
x=9 cm
3x=3×9=27
sum of diagonals=x+3x=4x=4×9=36 cm
Answer:
f(x)=nx
or
f(x)=9.50x
Step-by-step explanation:
Let x be the amount of hours and n be the hourly rate (9.50).

or if you prefer to use 9.50 instead of n, the function would be:

Answer: ![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Step-by-step explanation:

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;


Divide by m to isolate
.


To eliminate the square and isolate v, extract the square root.
![\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3D%5Csqrt%5B%5D%7Bv%5E2%7D)
![\sqrt[]{\frac{2K}{m} }=v](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D%3Dv)
let's rewrite it in a way that v is in the left side.
![v=\sqrt[]{\frac{2K}{m} }](https://tex.z-dn.net/?f=v%3D%5Csqrt%5B%5D%7B%5Cfrac%7B2K%7D%7Bm%7D%20%7D)
Answer:
$0.22
Step-by-step explanation:
Ellen has a coupon of 1.55 off a loaf of bread
The regular price of the bread is 4.63, the loaf is cut into 14 slices
Therefore if she uses her coupon the price per slice can be calculated as follows
= 4.63-1.55
= 3.08
3.08/14
= 0.22
Hence the price is $0.22