Answer:
0.25%
Explanation:
20 people start the new population. So there are 20 genes or 40 alleles for the recessive disorder phenylketonuria. 2 out of 40 alleles are recessive for the condition hence frequency of the allele = 2/40 = 0.05
Frequency of the allele does not change when the population increases so it is in Hardy-Weinberg equilibrium. According to it, if q is the frequency of recessive allele, q² = frequency of the recessive condition
Here, q = 0.05 So,
q² = (0.05)² = 0.0025
In percentage, it is 100 * 0.0025 = 0.25%
Hence, incidence of phenylketonuria in the new population is 0.25%
The probability that they both were planted alone is 0.3325.
<h3>What is genetic probability?</h3>
Probability serves to mathematically estimate the possibility of events that happen by chance, that is, as a matter of luck.
In this case:
- Number of plants planted alone = 134
- P(both plants were planted alone) = 134/232 x 133/231 = 0.3325
So the probability that both were planted alone is 0.3325.
See more about genetic probability at brainly.com/question/851793
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The correct choice is the third movement of continents
Answer:
-110 N
Explanation:
Una carga de 50 N unida a un resorte que cuelga verticalmente estira el resorte 5cm. El resorte se coloca ahora horizontalmente sobre una masa y se estira 11cm. ¿Qué fuerza se requiere para estirar ese resorte en esa cantidad?
Solution:
La constante de resorte (k) es la relación entre la fuerza (F) y la extensión (d) como resultado de la fuerza aplicada, por lo tanto:
k = F / d
Dado que F = 50 N, d = 5 cm = 0.05 m. Por eso:
k = F / d = 50 N / 0.05 = 1000 N / m
La fuerza (F) requerida para provocar un estiramiento de 11 cm se da como:
F = -kx
x = 11 cm = 0,11 m. Por eso:
F = -kx = -1000 * 0,11 = -110 N
El signo negativo significa que el objeto se tira hacia el resorte.
