To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
6 crackers, 9 marshmallows
Step-by-step explanation:
You have to divide to find how many graham crackers and marshmallows are needed to make 1 s'more:
8 / 4 = 2, so 2 crackers per s'more. Then,
12 / 4 = 3, so 3 marshmallows per s'more. Now that we know this, all we have to do is multiply each number by 3 to make 3 s'mores.
2 * 3 = 6, so 6 crackers, and
3 * 3 = 9, so 9 marshmallows.
:)
I don’t see the picture if I see it I can help you tho
If Susan had 2$ and got to 12$ we need to find what multiplied by 2 = 12. So, 12/2=6
If 6x2=12 then 11x6=66
66$
