Answer:
turning it I think.........
A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros

Now we multiply it to get the polynomial

polynomial function of least degree with integral coefficients that has the
given zeros 
Learn more : brainly.com/question/7619478
Solve for x over the real numbers:
3 x^2 + 5 x + 1 = 0
Hint: | Using the quadratic formula, solve for x.
x = (-5 ± sqrt(5^2 - 4×3))/(2×3) = (-5 ± sqrt(25 - 12))/6 = (-5 ± sqrt(13))/6:
Answer: x = (-5 + sqrt(13))/6 or x = (-5 - sqrt(13))/6
Step-by-step explanation:
220000/100=2200*0.49=789