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swat32
3 years ago
14

Provide examples of the cost of quality based on your own experiences

Computers and Technology
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

Cost of quality is define as methodology which basically decide the cost of product and services in an organisation and company. It also determine all the cost which are associated with the quality.

The cost of quality basically divided into four categories that are:

  • Appraisal
  • Prevention
  • External failure
  • Internal failure

Example of the cost of quality is that, in oil refinery industry if the growth of product increased then, the company state also increased. In same way, if there is decrease in the refining state of the product then, the growth of product automatically reduced.

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Which of the following statements is true about scalability? Choose 3 options.
Simora [160]

Answer:

4, 5, 2

Explanation:

just did it on edge :)

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3 years ago
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The Hudson Engineering Group (HEG) has contacted you to create a conceptual model whose application will meet the expected datab
alexdok [17]

Answer:

The diagram of the ER and depreciation is in the attachments.

3 0
3 years ago
Let's consider a long, quiet country road with houses scattered very sparsely along it. (We can picture the road as a long line
Rus_ich [418]

Answer:

Follows are the solution to these question:

Explanation:

A simple gullible algorithm is present. Let h mark the house to the left. Then we put a base station about 4 kilometers to the right. Now delete and repeat all the houses protected by this base station. In this algorithm, they can simply be seen to position baselines at b1, . . , bk as well as other algorithms (which may be an optimum algorithm) at b'_{1}, \ . . . . . . ,b'_{k'}  and so on. (from left to right)   b_1 \geq b'_{1},\ \  b_2 \geq b'_{2} That's why k \leq k'.

7 0
2 years ago
Series-connected 11-pF and 21-pF capacitors are placed in parallel with series-connected 22- pF and 30-pF capacitors. Determine
Naya [18.7K]

Answer:

19.9 pF

Explanation:

Given that:

Series connection :

11pF and 21pF

C1 = 11pF ; C2 = 21pF

Cseries = (C1*C2)/ C1 + C2

Cseries = (11 * 21) / (11 + 21)

Cseries = 7.21875 pF

C1 = 22pF ; C2 = 30pF

Cseries = (C1*C2)/ C1 + C2

Cseries = (22 * 30) / (22 + 30)

Cseries = 12.6923 pF

Equivalent capacitance is in parallel, thus,

7.21875pF + 12.6923 pF = 19.91105 pF

= 19.9 pF

8 0
3 years ago
_____ returns the smallest integer greater than or equal to 7.3
Artist 52 [7]

Answer:

Explanation:

Required

Which returns smallest integer greater than or equal to 7.3

i.e.

x \le 7.3

When executed, the result of each instruction is:

ceil(7.3) = 8 -- This returns the smallest integer greater than 7.3

floor(7.3) = 7 --- This returns the smallest integer less than 7.3

<em></em>larger(7.3)<em> --- there is no such thing as larger() in python</em>

round(7.3) = 7 --- This rounds 7.3 to the nearest integer

From the above result,

8 is the smallest integer greater than or equal to 7.3

i.e.

8 \ge 7.3

Hence:

ceil(7.3) is correct

5 0
3 years ago
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