Matter. because matter surrounds us all and helps us move and change.
Answer:
def rec_dig_sum( num ):
num_list = [ digit for digit in str(num)]
total = 0
for x in num_list:
total += x
return total
def dict_of_rec_dig_sums(low, high):
mydict = dict()
for number in the range(low, high+1):
mydict[rec_dig_sum(number)] = number
return mydict
Explanation:
The python program defines two functions, "rec_dig_sum" and "dict_of_rec_dig_sums". The former accepts a number and returns the sum of the digits of the number while the latter accepts a low and high number range.
The program returns a dictionary with the recursive sum as the keys and the number count as the values.
Answer:
The correct answer for the given question is " The Code fragment A runs fastly than the code fragment of B".
Explanation:
In this question there are some information is missing i. e options. The question does not give any options. The options for the given question is given below
(A.) The Code fragment A runs fastly than the code fragment of B.
(B.) The Code fragment B runs fastly than code fragment of A.
(C) The Code fragment A runs as fastly as code fragment of B.
So we conclude the answer i.e option(A) because As given in the question list1 is a MyArrayList and list2 is a MyLinkedList. , in list1 we fetching the data easily and fastly means that it remove the data easily as compare to list2 As MyArrayList is storing the list only and also we can fetch the data easily manner.
The list2 is an object of MyLinkedList means that it manipulating the data fastly as compared to MyArrayList but if we compared the fetching of data then MyArrayList is a better option so the code fragment runs fastly then code fragmented B.
D. Rasterize
This answer makes the most since
