<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Server and network is 2 different things, just put the server on a different network. ;) duh
Explanation:
Answer:
Explanation:
The following procedure is written in Python. It takes the next argument, checks if it is an odd number and if so it adds it to oddsum. Then it asks the user for a new number from the keyboard and calls the accumulator procedure/function again using that number. If any even number is passed the function terminates and returns the value of oddsum.
def accumulator(next, oddsum = 0):
if (next % 2) != 0:
oddsum += next
newNext = int(input("Enter new number: "))
return accumulator(newNext, oddsum)
else:
return oddsum
Explanation:
CATEGORIA GRAMATICAL PARIS
Paris es sustantivo.
What was the options they gave you?
