I think the answer is B. Because if you multiply 6x8 it’s 48 divided by 2 equals 24
Answer:
hi your question lacks the necessary matrices attached to the answer is the complete question
1024 bytes
Explanation:
A) The minimum size of the cache to take advantage of blocked execution
The minimum size of the cache is approximately 1 kilo bytes
There are 128 elements( 64 * 2 ) in the preceding simple implementation and this because there are two matrices and every matrix contains 64 elements .
note: 8 bytes is been occupied by every element therefore the minimum size of the cache to take advantage of blocked execution
= number of elements * number of bytes
= 128 * 8 = 1024 bytes ≈ 1 kilobytes
Answer:(1) To manage the computer's resources, which includes central processing unit, memory, disk drives, and printers, (2) To establish a user interface
(3)To execute and provide services for applications software.
The old mainframe computers have
(1) low memory sizes
(2) slower connectivity speed
(3) Larger sizer
(4) low sophistication.
Explanation: Operating system is a system software that manages the computer resources,helps to establish user interface and it helps to provide services for application softwares.
Operating system software includes WINDOWS X,WINDOWS 7,WINDOWS 8,LINUX,etc.
Mainframe computers are computers used by large multinational companies for processing bulk data. Old mainframe computers were produced by IBM(INTERNATIONAL BUSINESS MACHINE) in the year 1952 they are classed two scientific and commercial mainframe computers with different information although they had some incompatibilities. Old mainframe computers are large in size with low processing speed, sophistication and storage compared to present day system.